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Equation of the Week #4: Euler's identity

Posted by DarthWho on May 7, 2011 at 10:25 PM

Sorry for the delay I had extensive computer problems and then had to get used to a new machine:

e ^ (π * i) + 1 = 0

now for the reason behind this: 

e ^ (i * x) = COS(x) + i * SIN(x)

SIN(π) = 0

COS(π) = -1

NEXT WEEK(well tonight really): square roots of complex numbers (A+Bi)

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