|Posted by DarthWho on December 5, 2011 at 8:10 AM||comments (0)|
as I was going to do the finishing work on it I ended up having to catch several dozen fancy guppy fry; I hope to have it up by Wednesday wish me luck. sorry for ay inconveniences.
|Posted by DarthWho on November 29, 2011 at 7:55 AM||comments (1)|
this is only a test entry to attempt to reslove the mathml problems it will be deleted once the problem is resolved
this should display the quadratic formula;
x = − b ± b 2 ...Read Full Post »
|Posted by DarthWho on November 24, 2011 at 9:35 AM||comments (0)|
Now this is not really a true "equation of the week" entry as it features no equations;
Now why should you as a programmer know calculus? Is it the only path to being a great Programmer? Well no it is not some magical pathway leading to you becoming one of the pantheon of programming gods; there are many paths to being a great programer; Here is why I think you should have some understanding of calculus under your belt: you will be better equipped to solve any problems that may come you...Read Full Post »
|Posted by DarthWho on November 23, 2011 at 11:45 PM||comments (1)|
Sorry for the huge delay in getting this one up my bad.
how fo we calculate a^b when both A and B are complex numbers?
well this is where the complex exponentiation formula comes into play (this is a long one so hold onto your hats!
well first we have the formula:
how do we work that out you ask? well it just so happens that that formula is equal to:
E+Fi=(A^2+B^2)^(C/2)*e^(-D*ARG(A+Bi))*(COS(C*ARG(A+Bi)+D*ln(A^2+B^2)/2)+i*S...Read Full Post »
|Posted by DarthWho on May 22, 2011 at 12:00 AM||comments (1)|
the complex argument is a function which is comonly used in functions such as complex exponentiation; it is a function which takes a Complex number and returns a real number to put it into easy to understand terms:
ARG(X + i * Y) = ARCTAN(Y / X)
Or to put it in terms of qb64 code:
ARG(X + i * Y) = ATN(Y / X)
NEXT WEEK: COMPLEX EXPONENTIATION
|Posted by DarthWho on May 15, 2011 at 12:00 AM||comments (0)|
Complex numbers are not as difficult as they may first appear to be; this numeric system which is traditionally written in the form of:
A + B * i
Is the second of the division maths to be discovered; this is because like the real numbers the complex numbers are capable of being divided: however the complex numbers could also be written as
which...Read Full Post »
|Posted by DarthWho on May 8, 2011 at 12:00 AM||comments (1)|
Any one who is sufficiently well versed in number theory understands that the squareroot of a negative number produces what is known as an imaginary number:designated by the symbol i but then what is the squareroot of i or for that matter any of the general group of the complex numbers (a+b*i)?
well here is your answer:
√(A+B*i)=√((A + √(A2 + B2))/2) + SGN(B) * √((-A + √(A2 + B2))/2) * i
which for i...Read Full Post »
|Posted by DarthWho on May 7, 2011 at 10:25 PM||comments (0)|
Sorry for the delay I had extensive computer problems and then had to get used to a new machine:
e ^ (π * i) + 1 = 0
now for the reason behind this:
e ^ (i * x) = COS(x) + i * SIN(x)
SIN(π) = 0
COS(π) = -1
NEXT WEEK(well tonight really): ...Read Full Post »
|Posted by DarthWho on May 1, 2011 at 10:56 PM||comments (0)|
Osama Bin Laden Is finally Dead. story: http://abcnews.go.com/Blotter/osama-bin-laden-killed/story?id=13505703
I justy wonder what is going to come of this.
|Posted by DarthWho on April 24, 2011 at 12:00 AM||comments (1)|
Sorry for the rather simple equation this week. Finals are coming up so I do not have alot of time. Anyway onto what you are really reading this for:
n = c/v
n is the index of refration and is unit less
c is the speed of light in a vacuum (299,792,458 m/s) any unit system may be used
v is the velocity of light in the substanced again any unit system may be used but it must be the same system used for the speed of light.
Read Full Post »